2年級英語上冊n版

題目給我，我告訴你

3. wants to know to draw
4. do
5. go shopping does shopping
6. making play
7. Watching is
8. hopes to be
9. Does listen
10. does do

首先困頃(1+1/磨扮x)^(x+1)>e（單調(diào)減極限是e）即e*x^(x+1)<(x+1)^(x+1)
下用數(shù)學(xué)歸納法證明
如果命題對n成立（原式等價于1^n+2^n+…+n^n則1^(n+1)+2^(n+1)+…瞎尺灶+n^(n+1)+(n+1)^(n+1)
<=n*(1^n+2^n+…+n^n)+(n+1)^(n+1)
<=n*e/(e-1)*n^n+(n+1)^(n+1)
<=e/(e-1)*n^(n+1)+(n+1)^(n+1)
<=1/(e-1)*(n+1)^(n+1)+(n+1)^(n+1)
=e/(e-1)*(n+1)^(n+1)

完美公主VS帥氣管家

一只兔子三條色龍

O(∩_∩)O哈哈~ 里德

TO LOVE

x∧n-x∧n-2
=x∧n-x∧n÷4
=(1-1/4)x∧n
=3/4x∧n。

就是N項(xiàng)之后滿足條件就行.這體現(xiàn)了極限的本質(zhì),反映了后面無窮多項(xiàng),不管前有限項(xiàng)是什么.